Question

if -4 is the zero of the polynomial p (x)=x2+11x+k, then value of k is

Answer 1

Heya!
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◾Given that ,
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⭐ -4 is a root of p (x) => x² + 11x + k

✔This implies that ,

x => -4 should turn the equation zero .

↪Put x = -4 in p (x)

=> (-4)² + 11 (-4) + k = 0

=> 16 - 44 + k = 0

=> -28 + k = 0

=> K = 28


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Answer 2

p (-4) = (-4)2+11(-4)+k
= -8-44+k
= -52+k
k = 52