If - 4 is the zero of the polynomial x-x-(2+2) then find the value of k.
Answers
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Step-by-step explanation:
-4-(-4)-(4)=-4+4-4=-4
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Your question would probably be:
If - 4 is the zero of the polynomial x²- x- ( 2k + 2 ) then find the value of k.
Answer: k = 9
Solution:
Given polynomial:
= x²- x- ( 2k + 2 )
Let
p(x) = x²- x- ( 2k + 2 )
Given that: -4 is a zero of the polynomial,
∴ when x = -4 ,
p(-4) = 0 ------------------------------------------------------( 1 )
Putting x = -4 in p(x), we get:
p(-4) = (-4) ²- (-4) - ( 2k + 2 ) = 0 ----------------------------(By 1)
= (-4) ²- (-4) - ( 2k + 2 ) = 0
⇒ 16 + 4 - ( 2k + 2 ) = 0
⇒ 20 - 2k - 2 = 0
⇒ 2 ( 10 -k -1 ) = 0
⇒ 10 - k - 1 = 0
⇒ 9 - k = 0
⇒ -k = -9
⇒ k = 9
Hope you understood the method of solving.
Thank You.
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