Math, asked by eswararaosetti213, 1 month ago


If - 4 is the zero of the polynomial x-x-(2+2) then find the value of k.​

Answers

Answered by vinothiniindu
0

Step-by-step explanation:

-4-(-4)-(4)=-4+4-4=-4

Answered by KnowtoGrow
0

Your question would probably be:

If - 4 is the zero of the polynomial x²- x- ( 2k + 2 ) then find the value of k.​

Answer: k = 9

Solution:

Given polynomial:

= x²- x- ( 2k + 2 )

Let

p(x) = x²- x- ( 2k + 2 )

Given that: -4 is a zero of the polynomial,

∴ when x = -4 ,

p(-4) = 0       ------------------------------------------------------( 1 )

Putting x = -4 in p(x), we get:

p(-4) = (-4) ²- (-4) - ( 2k + 2 ) = 0 ----------------------------(By 1)

= (-4) ²- (-4) - ( 2k + 2 ) = 0

⇒ 16 + 4 - ( 2k + 2 ) = 0

⇒ 20 - 2k - 2 = 0

⇒ 2 ( 10 -k -1 ) = 0

⇒ 10 - k - 1 = 0

⇒ 9 - k = 0

⇒ -k = -9

⇒ k = 9

Hope you understood the method of solving.

Thank You.

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