If -4 is the zero of the polynomial x3 - x2 - 14x +24 find the other zeroes.
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khanujarashmit:
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Answered by
7
Answer:
Other Zeroes are 2 and 3
Step-by-step explanation:
Given: -4 is factor of x³ - x² - 14x + 24
To find: Other zeroes.
x = -4 is a zero of the polynomial then ( x + 4 ) is factor the the polynomial.
On dividing the given polynomial with factor,
Quotient = x² - 5x + 6
Division is in pic.
So,
x³ - x² - 14x + 24 = ( x + 4 ) ( x² - 5x + 6 )
= ( x + 4 ) ( x² - 3x - 2x + 6 )
= ( x + 4 ) ( x( x - 3 ) - 2( x - 3 ) )
= ( x + 4 )( x - 3 )( x - 2)
Now, To find zeroes,
x³ - x² - 14x + 24 = 0
( x + 4 )( x - 3 )( x - 2) = 0
x - 3 = 0 and x - 2 = 0
x = 3 and x = 2
Therefore, Other Zeroes are 2 and 3
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