Question

if -4 is zero of the polynomial x^2-x-(2+2k) then the value of k

Answer 1

Step-by-step explanation:

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Answer 2

Solution

Given =》

▪︎ x²-x-(2+2k)

One Zero -4

Need to find =》

Value of k

Explanation =》

p(x) = x²-x-(2+2k)=0

g(x) = x = -4

putting x=-4 in p(x)

p(x) = x²-x-(2+2k)

= x²-x-2-2k

= (-4)²-(-4)-2-2k=0

= 16+4-2-2k=0

= 20-2-2k=0

= 18-2k =0

= -2k = -18

= k=9

So , the value of k is 9