Question

If -4 is zero of the polynomial x^2-x-(2+2k) then the value of k is what

Answer 1

p(x) = 0
$p(x) = {x}^{2} - x - (2 + 2k)$
$0 = ({ - 4}^{2}) - ( - 4) - (2 + 2k)$
0 = 16 + 4 - 2 - 2k
18 - 2k = 0
2k = 18
k = 19

Answer 2

Hello mate !!!!!!!!

Here is ur answer...

P(x) = x^2 - x - (2 + 2k)

P(-4) = 0

-4^2 -(- 4) -(2+2k) = 0

16 +4 - 2 - 2k = 0

20 - 2 - 2k = 0

18 - 2k = 0

2(9-k) = 0

9 - k = 0/2

- K = 0 - 9

- K = - 9

K = 9

HOPE THIS WILL HELP YOU ....