Question

if 4 moles of nitrogen reacts with 20 moles of hydrogen how many nh3 moles are produced​

Answer 1

Answer:

Given:

Reaction of Hydrogen and Nitrogen is given to form Ammonia.

4 moles of hydrogen reacts with 20 moles of hydrogen.

To find:

Moles of ammonia produced.

Concept:

A reaction forming products is governed according to the amount of limiting reagent present in the system.

Calculation:

$\boxed{ \red{N_{2} + 3H_{2} \: \rightarrow \: 2NH_{3}}}$

So we can say that in ideal conditions; 1 mole of Nitrogen react with 3 mole of hydrogen to form 2 moles of Ammonia.

So, here nitrogen is the limiting reagent and hydrogen is the excess reagent.

Because as per Unitary method,

4 moles of nitrogen shall react with 12 moles of hydrogen (but 20 moles have been provided).

So moles of Ammonia produced

= 4 × 2

= 8 moles.

Amount (in gm) of ammonia produced

= 8 × 17

= 136 gm.

So final answer :

$\boxed{ \blue{amount \: = 136 \: gm}}$