Question

if 4 moles of Sulphur dioxide are oxidized to sulphur trioxide how many moles of oxygen molecules are required?​

Answer 1

Answer:

Look at the equation for the reaction.

2SO2 +O2 = 2SO3

These tell you the relative number of molecules involved. 2 sulphur dioxide; 1 oxygen; 2 sulphur trioxide.

A mole is simply a huge number just as ‘a dozen’ is a relatively small number.

2 dozen SO2 + 1 dozen O2 = 2 dozen SO3

2 moles SO2 + 1 mole O2 = 2 moles SO3

So if you start with 4 moles of SO2 you’ll need half a much moles of O2

Answer 2 moles of O2 will be needed

Explanation:

Answer 2

Answer:

Explanation:

equivalent of so2 = equivalent of o2

moles*f= moles*f

8 = moles*4

moles=2

alter

poac of s

moles of so2 = moles of so3

poac of  o

2 moles of so2 + 2 moles o2 = 3 moles of so3

2 moles of o2 = moles of so2

moles of o2 = moles of so2 / 2

moles of o2 = 4

alter

so2+o2 = so3

balance above by reverting valency factors

4so2 + 2o2 = so3

4so2 +2o2 = 4so3

moles of so2 / moles of o2 = c1/c2

moles of o2 = moles of so2 (c2/c1)

moles of o2 = 4(2/4) = 2

alter

as here it is not a limiting reagent and both are equal

moles/sc = moles/sc

moles/4 = moles/2

moles/2= moles of o2

2 = moles of o2