Math, asked by Nupurguptak6930, 10 months ago

If 4+root 5 is a root of equation y2-8y+m = 0 where m is rational

Answers

Answered by tabrez707071
0

Step-by-step explanation:

LHS of the given equation is:

rationalising the denominator, we have

RHS is

therefore

equating the rational and irrational parts from the both sides of the equation:

hope this helps you.

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student-nameAwesum answered this

146 helpful votes in Math, Class X

3+ root 7/3-root7

=(3+root 7)whole square /3 square-root 7 square

=3 square+ root7 square+2*3* root 7/9- root 49

=9+root 49+6 root 7/9-7

=9+7+6 root 7/2

=16+6 root 7/2

16+6root7/2 = a+b root7

a=16/2=8

b=6/2=3 جھنک سلام

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Answered by shaivya2712
0

Answer:

Step-by-step explanation:

Since the root given is positive

so we will apply the rule

So,

-b+√b^2-4ac/2a= 4+√5

-(-8) +√64-4m/2=4+√5

8+√64-4m= 8+2√5

64-4m=20

4m=44

m=11.

Answer.

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