Question

If 4 root of the equaction x
$x ^{2} + ax - 8 = 0$
then a=
​

Answer 1

Given:-

• Quadratic Equation → x²+ax-8 = 0
• Root of the equation = 4

To Find:-

• Value of a

Solution:-

Value of x = 4

Substitute x = 4 in the Q.E

→ (4)²+a4-8 = 0

→ 16+a4-8 = 0

→ 16+a4 = 8

→ a4 = 8-16

→ a = -8/4

→ a = -2

∴ Value of a = -2.

$\Large{✓}$

Hope It Helps You ✌️

Answer 2

a = -2

Step-by-step explanation:

According to the question, we are given a quadratic equation:

x² + ax -8 = 0

We are also given one root of the equation: 4.

We need to find the value of a.

Since one of its roots is 4, this implies that x = 4. Our job is to substitute the value of 4 in the given quadratic equation.

→ x² + ax - 8 = 0

→ (4)² + 4a - 8 = 0 [x = 4]

→ 16 + 4a - 8 = 0

→ 8 + 4a = 0

→ 4(2 + a) = 0

→ 2 + a = 0

→ a = -2

Finally, we have got our value of a as -2.

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