Question

If 4 sec^2 a - 7 tan^2 a=3, show that sin^2 a = +-1/2​

Answer 1

Answer:

he mate here your answer:---

Step-by-step explanation:

we know that ..

sec^2a-tan^2a=1.

then put value of sec in given equation.....

it will be..

4(1+tan^2a)-7tan ^2a=3.

-3tan^2a=-1.

tan ^2a=1/3.

tan a= ±(1/3)^1/2.

THEN ..

SIN a=±1/2.

or

sin^2a=±1/4

that's proved.

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Answer 2

Answer:

Step-by-step explanation:

4Sec²A - 7tan² A = 3

[Sec² = 1 + tan² ]

4(1 + tan²A) - 7tan²A =3

4 +4tan²A -7tan² A = 3

4 - 3tan² = 3

3tan²A = 1

tan a = 1/√3

A= 30°

Sin² A

Sin² 30°

Sin ² 30° = 1/2

Sin 30= ± 1√ 2

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