If 4 sin-1x + cos2x = , then : X
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Answer:
Hope it helps you
Step-by-step explanation:
We have 4sin
4
x+cos
4
x=1
⇒4sin
4
x=1−cos
4
x=(1−cos
2
x)(1+cos
2
x)=sin
2
x(2−sin
2
x)
⇒sin
2
x[5sin
2
x−2]=0
⇒sinx=0 or sinx=±
5
2
⇒x=nπ or x=nπ±sin
−1
5
2
,(n∈Z)
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