If 4 sin^2 theta = 1 then value of theta is .
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Answer:
Ф = n π + ( - 1 ) ⁿ π / 6
Explanation:
Given :
4 sin² θ = 1
sin² θ = 1 / 4
sin θ = 1 / 2
sin θ = sin π / 6
Using General method i.e. sin θ = sin α
Then :
Ф = n π + ( - 1 ) ⁿ α
For this case :
Ф = n π + ( - 1 ) ⁿ π / 6
Hence we get answer .
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