Physics, asked by Anonymous, 11 months ago

If 4 sin^2 theta = 1 then value of theta is .

Answers

Answered by believe123
2

Answer:

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Answered by Anonymous
13

Answer:

Ф = n π + ( - 1 ) ⁿ  π / 6

Explanation:

Given :

4 sin² θ = 1

sin² θ = 1 / 4

sin θ =  1 / 2

sin θ = sin π / 6

Using General method i.e. sin θ = sin α

Then :

Ф = n π + ( - 1 ) ⁿ  α

For this case :

Ф = n π + ( - 1 ) ⁿ  π / 6

Hence we get answer .

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