If 4 sin +3 cos =p and 4 cos -3 sin =q , then the value of p²+q² is
1)24
2)50
3)48
4)25
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2
Answer:
25
Step-by-step explanation:
Let sinA = a, cosA = b.
⇒ 4a + 3b = p ; 4b - 3a = q
Square on both & add:
⇒ (4a + 3b)² + (4b - 3a)² = p² + q²
⇒ (4a)² + (3b)² + 2(12ab) + (4b)² + (3a)² - 2(12ab) = p² + q²
⇒ (4a)² + (4b)² + (3a)² + (3b)² = p² + q²
⇒ 4²(a² + b²) + 3²(a² + b²) = p² + q²
⇒ 16(sin²A + cos²A) + 9(sin²A + cos²A) = p² + q²
⇒ 16(1) + 9(1) = p² + q²
⇒ 25 = p² + q²
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