Question

. If

4

sin

5

  and  is not in the first quadrant

then the value of cos .

1) –

3

5

2)

3

5

3)

1

2

4) –

1

2

37.  is not in 4th quadrant, tan = – 4/3 then

5sin+10cos+9sec +16cosec+4cot =

1) – 1 2) 2/5 3) 4/5 4) 0

38. If cot =

p

q

then find

sin cos

sin cos

p q

p q

 

 

 



1) 0 2) 1 3) 2 4) 3

39.        

  

2 2

2 2

1 cosec sec is acute, tan

7 cosec sec

1)

3

4

2)

1

2

3) 2 4)

5

4

40. If

3

cos

5

  and  is not in the first quadrant, then

   

   

5 tan 4 cos

5sec 2 4cot 2

   

   

  



  

1)

4

5

2)

4

5

 3)

5

4

4)

5

4



41.  

2 0 0 1 cos 200 cos ec 200  

1) – 1 2) 0 3) 1 4) 2

42.  

2 0 0 1 sin 200 sec 200  =

1) – 1 2) 0 3) 1 4) 2

43. 



1 cos A

1 cos A

= k (cosecA + cotA)  k =

1) – 1 2) 1 3)  1 4) 2

44. If

1 sin

sec tan

1 sin

A

A A

A



 



, then A lies in the

quadrants

1) I, II 2) II, III 3) I, III 4) I, IV

Based on quadrants :

45. If cosec  + cot  =

1

3

, determine the quadrant in which

 lies.

1) I 2) II 3) III 4) IV

46. If cos cot 5 ec then      lies in the quadrant

1) I 2) II 3) III 4) IV​

Answer 1

Answer:

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