Question

If 4 sinA - 3 cos A = 0, find the value of 12 sinA-7 cosA/8 sinA+3cosA
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Answer 1

Step-by-step explanation:

4sin A - 3cosA=0

divide it both by cosA you get

4sinA/cosA-3cosA/cosA=0

4tanA-3=0

4tanA=3

tanA=3/4

now aplly trigonometric ratio

to find hypotenuse

you get 5

now put all the values wat u get

12×3/5-7×4/5 whole divided by 8×3/5+3×4/5

36-28÷5 divided by 24+12÷5

8÷36

2/9 answer