Question

if 4 sinA = 3 cosA find the value of cosA​

Answer 1

Answer:

let base=b perpendicular=p hypotenuse=h

4 sin A=3cos A

sin A/cos A=3/4

p/h ÷ b/h=3/4

p/h×h/b=3/4

p/b=3/4

tan A =3/4=perpendicular/base

(h)^2=(p)^2+(b)^2

h^2=(3)^2+(4)^2

h^2=9+16

h^2=25

h=5

cos A =b/h =4/5...(ans)