If 4 tan 0 = 3, evaluate
(4 sino - cos 0+1/
4 sin 0+ cos 0-1)
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Answered by
5
4 tan Θ = 3
tan Θ = 3/4
Let perpendicular be 3k and base be 4k.
Then hypotenuse = √(3k)²+(4k)² = √9k²+16k²=√25k²=5k
sin Θ = p/h = 3k/5k = 3/5
cos Θ = b/h = 4k/5k = 4/5
4 sin Θ - cos Θ + 1 = 4 x 3/5 - 4/5 +1 = 12/5 - 4/5 - 5/5 = 3/5
4 sin Θ + cos Θ -1 = 4 x 3/5 + 4/5 +1 = 12/5 + 4/5 - 5/5 = 11/5
Answered by
1
Answer:
4 tan 0=3
tan 0=3/4
sin o/cos 0=3/4
4 sin 0=3 cos 0
given:
(4 sin 0- cos 0+1/4 sin 0+cos 0-1)
= (3 cos 0-cos 0+1/3 cos 0+cos 0-1)
= (2 cos 0+1/4 cos 0-1)
Step-by-step explanation:
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