if 4 tan 0 =3 find the value of
4 sin 0_ cos 0+1/ 4sin0+ cos0+1
Answers
Answered by
0
Answer:
Given 4Tanθ=3⇒Tanθ=
4
3
sinθ=
5
3
cosθ=
5
4
4sinθ+cosθ
4sinθ−cosθ
=
4(
5
3
)+
5
4
4(
5
3
)−
5
4
=
5
16
5
8
=
2
1
Answered by
1
Step-by-step explanation:
If 4tan=3
then, tan=3/4=P/B
Now, P=3 and B=4.
H=√P^2+B^2
=√3^2+4^2
=√9+16
=√25
=5 .
Hope it is useful for you.
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