Math, asked by aadityasinghalyo30, 10 months ago

if 4 tan a =3 evaluate 4sina-3cosa/4sina+2cosa

Answers

Answered by 05manisha2000
2

Step-by-step explanation:

4tan a= 3

=> tan a=3/4

=>p/b=3/4

=>p =3,b=4, h=√p²+b²

=√3²+4²

=5

sin a=p/h =3/5

cos a=b/h=4/5

4sin a -3cos a /4sin a +2cos a

=4*(3/5) -3*(4/5)/4*(3/5)+2*(4/5)

=(12/5)-(12/5)/(12/5)+(8/5)

=(12/5)-1+(8/5)

=(12-8)/5-1

=4/5-1

=-1/5

Answered by swethassynergy
1

The value of 4sina-\frac{3cosa}{4sina} +2cosa is 3.

Step-by-step explanation:

Given:

If 4\ tan \ a =3.

To Find:

The value of 4sina-\frac{3cosa}{4sina} +2cosa .

Solution:

As given,If 4\ tan \ a =3.

4\ tan \ a =3.

tan\ a=\frac{3}{4}

p/b=3/4

p =3,b=4, h=√p²+b²

h=√3²+4²=5

sin\ a\ = \frac{3}{5}

cos\ a\ = \frac{4}{5}

The value of 4sina-\frac{3cosa}{4sina} +2cosa    =4\times\frac{3}{5} -\frac{3\times\frac{4}{5} }{4\times\frac{3}{5} } +2\times \frac{4}{5}

                                                           =\frac{12}{5} -\frac{\frac{12}{5} }{\frac{12}{5} } +\frac{8}{5}

                                                          =\frac{12}{5} -1 +\frac{8}{5}

                                                          =\frac{12}{5} +\frac{8}{5}-1

                                                          =\frac{20}{5} -1

                                                          =4-1=3

                                                                                     

Thus,The value of 4sina-\frac{3cosa}{4sina} +2cosa is 3.

#SPJ3

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