Question

if 4 tan A=3, find the value of following expression: 4sinA+3cosA / 4sinA-2cosA​

Answer 1

Answer:

see the pic for answer

Step-by-step explanation:

Frnd your final answer is 25/10.

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Answer 2

$\blue{\boxed{Answer}}$

The value of (4sinA + 3cosA)/ (4sinA - 2cosA) is 6

Step-by-step explanation:

Given ,

$4 \tan A = 3 \\ \implies \tan A = \frac{3}{4} \\ \implies \frac{ \sin A}{ \cos A } = \frac{3}{4} \\ \implies4 \sin A = 3 \cos A$

We are given in the question : find the value of

$\frac{4 \sin A + 3 \cos A }{4 \sin A - 2 \cos A }$

So putting the value 4sinA = 3cosA we have

$\frac{4 \sin A + 3 \cos A }{4 \sin A - 2 \cos A } \\ = \frac{3 \cos A + 3\cos A}{3\cos A - 2\cos A} \\ = \frac{6\cos A}{\cos A} \\ = 6$

Formula Used

$\tan \theta = \frac{ \sin \theta}{ \cos \theta}$