Question

if
4 tan A=3 Then find
of Sin A+ cosA/secA+cosecA

​

Answer 1

Answer:

= 4/5√5 is the answer

Step-by-step explanation:

4 tanA =3

tanA = 3/4

1+tan²A = sec²A

1+(3/4)² = sec²A

1+9/16 = sec²A

16+9 /16 =sec²A

25/16 = sec²A

secA = 5/4

cosA = 1/secA

cos A = 4/5

sin²A + cos²A =1

sin²A + 4/5 = 1

sin²A 1-4/5

sin²A = 5-4/5

sinA =√1/5 =1/√5

sinA =1/cosecA

CosecA = √5

SinA + CosA / secA + cosecA

(1/√5 + 4/5) / (5/4 +√5)

(5+4√5 /5√5) / (5+4√5/4)

= 4/5√5