Math, asked by Shivank9761, 1 year ago

if 4 tan theta = 3 evaluate 4 sin theta - cos theta + 1 / 4 sin theta - cos theta -1​

Answers

Answered by deveshbaghel371
0

Answer:

Step-by-step explanation:

Given 4tan theta =3

Tan theta =3/4 and tan theta = p/b

So by Pythagorean theorem h = 5

Sin theta = p/h and cos theta = b/h

4*3/5 - 4/5 +1/4*3/5 -4/5-1

=( 48 +3-52)/20

= -1/20

Answered by duragpalsingh
4

Hey there! ☺☻☺

Given,

4 tan = 3

∴ tan = 3/4

As we know,

Tan  = Perpendicular / base

Tan  = 3/4

Now,

Hypotenuse = √3² + 4² = √9+16 = √25 = 5

Using this, we can find:

Sin = Perpendicular / Hypotenuse = 3/5

Cos = Base / Hypotenuse = 4/5

ATQ,

(4sin - cos + 1)/(4sin + cos - 1) 

= (4 × 3/5 - 4/5 + 1)/(4 × 3/5 + 4/5 - 1)   [putting values]

= (12 - 4 + 5)/(12 + 4 - 5) 

= 13/11

Hope It Helps You! ☺☻☺

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