if 4 tan theta=3 evaluate (4sin theta -cos theta +1 appon 4sin theta + cos theta -1
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Answered by
608
↑ Here is your answer ↓
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Let ∠A be '∅' (see figure.)
So, hypothenuse will be 5 by Pythagoras theorem.
Now,
5 will cancel out,
____________________________________________________________________________________________________________________________
Glad to help you.
@EmadAhamed
_____________________________________________________________
_____________________________________________________________
Let ∠A be '∅' (see figure.)
So, hypothenuse will be 5 by Pythagoras theorem.
Now,
5 will cancel out,
____________________________________________________________________________________________________________________________
Glad to help you.
@EmadAhamed
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Answered by
340
Solution :
[ Here I am using A instead of
theta ]
It is given that ,
4tanA = 3 ---( 1 )
tanA = 3/4
=> tan² A = 9/16
=> sec²A - 1 = 9/16
=> sec²A = 9/16 + 1
=> sec²A = ( 9 + 16)/16
=> Sec²A = 25/16
=> SecA = 5/4 ---( 2 )
Now ,
(4sinA-cosA+1)/(4sinA+cosA-1)
Divide numerator and denominator
With cosA, we get
(4tanA-1+secA)/(4tanA+1-secA)
= (3-1+5/4)/(3+1-5/4) [from(1)&(2)]
= (2+5/4)/(4-5/4)
Divide numerator and denominator
With 4 , we get
= ( 8 + 5 )/( 16 - 5 )
= 13/11
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