Question

if 4 tan theta=3 find (4sin theta-3cos theta/4sin theta+3 cos theta) pls answer it​

Answer 1

Given:

$\star \: 4 \tan \theta \: = 3 \\ or \: \\ \star \tan \theta = \frac{3}{4}$

To find:

$\star \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta}$

Solution:

$\implies \: \frac{4 \sin \theta - 3 \cos \theta}{4 \sin \theta + 3 \cos \theta}$

• Divide both numerator and denominator with cos@, we get :

$\implies \: \frac{ \frac{ 4 \sin \theta - 3 \cos \theta}{ \cos \theta} }{ \frac{4 \sin \theta + 3 \cos \theta}{ \cos \theta} } \\ \\ \implies \: \frac{4 \tan \theta - 3}{4 \tan \theta + 3}$

Now , put the value of tan@

$\implies \: \frac{4( \frac{3}{4}) - 3 }{4( \frac{3}{4}) + 3 } \\ \\ \implies \: \frac{3 - 3}{3 + 3} \\ \\ \implies \: \frac{0}{6} = 0$

Hence, the value is 0.

Answer 2

Step-by-step explanation:

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