Question

If 4 tanA = 3 , find the value of tan²A - sec²A *​

Answer 1

Answer:

tanA=3/4

Sec²A-tan²A=1

Sec²A-(3/4)²=1

Sec²A-(9/16)=1

Sec²A=1+(9/16)

Sec²A=25/16

SecA=5/4

=> cosA=1/secA

= cosA = 4/5

Answer 2

Answer:

-1

Step-by-step explanation:

4tanA = 3 => tanA = 3/4 = (opposite side)/(adjacent side)

=> hypotenuse = $\sqrt{(opposite side)^2 + (adjacent side)^2}$ = $\sqrt{3^2 + 4^2}$ = 5

secA = (hypotenuse)/(adjacent side) = 5/4

then, tan²A - sec²A is

= (3²/4²) - (5²/4²)

= 9/16 - 25/16

= -16/16

= -1