Question

If 4 tanA = 3 then find the value of

4cos + sin + 1

4cos + sin − 1​

Answer 1

Answer:

4 tanA=3

so, tanA= 3/4

tanA = p/b

so, perpendicular =3

base =4

so, hypotenuse =5

4cos + sin +1 = 4*4/5 +3/5 +1

=16/5 +3/5 +1

=(16+3+5)/5

=24/5=4.8

4cos +sin - 1 = 4*4/5+3/5-1

=16/5+3/5-1

=(16+3-5)/5

=14/5 =2.8