Question

if 4 tanQ=3 then find the value of 4sinQ-cosQ/4sinQ+cosQ​

Answer 1

4tanθ = 3 so,

tanθ = 3/4

Now, (4sinθ - cosθ)/(4sinθ + cosθ)

First of all divide cosθ with both LHS and RHS , (4sinθ/cosθ - cosθ/cosθ)/(4sinθ/cosθ + cosθ/cosθ) = (4tanθ - 1)/(4tanθ + 1)

Now, put tanθ = 3/4 = (4 × 3/4 - 1)/(4 × 3/4 + 1)

= (3 - 1)/(3 + 1) = 2/4 = 1/2

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Answer 2

Answer:

1/2

Step-by-step explanation:

tanQ=3/4

tanQ=perpendicular/base

hypotenuse =h

By PT,

h²=3²+4²

h²=25

h=5

sinQ=3/5 and cosQ=4/5

4sinQ-cosQ/4sinQ+cosQ=(4(3/5)-4/5)/(4(3/5)+4/5)

=8/16

=1/2