Question

if 4 tenA=3,then the value of 4sinA +cosA/8sinA+5cosA​

Answer 1

Answer:

TanA=4/3

perpendicular =4 cm

base=3cm

by pythogoras theorem

hypotenuse=5cm

sinA=4/5

cosA=3/5

in question.

4( \frac{4}{5} ) -  \frac{3( \frac{3}{5}) }{3( \frac{4}{5} )}  + 2( \frac{3}{5} ) \\  \frac{16}{5}  -  \frac{ \frac{9}{5} }{ \frac{12}{5} }  +  \frac{6}{5}  \\  \frac{22}{5}  -  \frac{9}{5}  \times  \frac{5}{12}  \\  \frac{22}{5}  -  \frac{9}{12}  =  \frac{22}{5}  -  \frac{3}{4}  \\  \frac{88 - 15}{20}  =  \frac{73}{20}

value is 73/20

I HOPE IT HELPS...

Answer 2

Answer:

$<marquee>$ Hope it help.