If 4 times the 4th term of an a.P. Is equal to 9 times the 9th term of the a.P., what is the 13th term of this a.P.?
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Answer:
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Step-by-step explanation:
to find nth term
Tₙ=a+(n-1)d
4(a+(4-1)d)=9(a+(9-1)d)
4a+12d=9a+72d
5a+60d=0
a+12d=0
whereas T₁₃=a+(13-1)d=a+12d
T₁₃=0
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