Question

if 4 times the 4th term of an AP is equal to 18 times its 18th term then find its 22nd term .
​

Answer 1

Answer:

a22=0

Step-by-step explanation:

given:

4a4=18a18

to find a22

we have

4a4=18a18

4(a+3d)=18(a+17d)

4a+12d=18a+306d

18a-4a=12d-306d

14a=-294d

14a+294d=0

14(a+21)=0

a+21d=0/14

a+(22-1)d=0

a22=0.

Answer 2

⭐⭐herr is your ans.⭐⭐

let first term = a

and common difference = d

according to the question :-

4(A4 ). = 18(A18)

so, 4(a+3d) = 18(a+17d)

-306d+12d =14a

-294d= 14a

so, 14(a+21d) = 0

14(A22) = 0

so, A22 = 0

☺hope it helps u☺