Question

if 4 times the area. of smaller square is subtracted from the area of largr square ,the result is 144m².the sum of the areas of the two squares is 464m².determine the sides of two squares.

Answer 1

Answer:

let side of smallest square Be X and bigger square be y

it is given that

• ${4x }^{2} - {y}^{2} = 144..........given \\ also \\ {x}^{2} + {y}^{2} = 464............given \\ adding \: both \: eqns \\ 5 {x}^{2} = 608 \\ {x}^{2} = \frac{608}{5 } \\ {x }^{2} = 121.6 \\ {x} = 11.12 \\ therefore \\ {x }^{2} + {y}^{2} = 464 \\ 121 + {y}^{2} = 464 \\ {y}^{2} = 464 - 121 \\ {y}^{2} = 343 \\ y = 18.52$