Question

if 4^x*2^y=128 and 3^3x+2y=9^xy then find the value of x and y.

Answer 1

hope it will help you..

Answer 2

Answer:

Step-by-step explanation:

4^x.2^y=128 and 3^3x+2y=9^xy is

2^2x.2^y=128

2^2x.2^y=2^7

3^3x+2y=9^xy

3^3x+2y=3^2xy

let the first equation be

2x+y=7-----1

y=7-2x

3x+2y=2xy-----2

3x+2(7-2x)=2x(7-2x)

3x+14-4x=14x-4x^2

4x^2-15x+14=0

4x^2-15x+14=0

4x(x-2)-7(x-2)=0

(4x-7)(x-2)

x=4/7 or x=2

now put the x value in y=6-2x

y=7-2(7/4)

y=7-7/2

y=7/2

or

y=7-2x

y=7-2*2

y=7-4

y=3

so x=7/4 or 2

    y=7/2 or 3