Math, asked by abhijotsingh600, 1 year ago

If 4^x - 4^x-1 = 24.. Find the value of (2x)^x .

Answers

Answered by Akv2
8
 {4}^{x} - {4}^{x - 1} = 24 \\ (4 - 1) \times {4}^{x - 1} = 24 \\ 3 \times {4}^{x - 1} = 24 \\ {4}^{x - 1} = 8 \\ {2}^{ 2 \times (x - 1)} = {2}^{3} \\ 2 \times (x - 1) = 3 \\ 2x - 2 = 3 \\ 2x = 5 \\ x = \frac{5}{2}

Value of x will be  \frac{5}{2}
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