Question

If 4^x-4^x-1=24, then find the value of x

Answer 1

4^x-4^x-1=24
=4^x-4^x=24+1
=4^x-4^x=25
=0≠25
(ANSWER)
{Note: Question has some error or the best answer is 0 can have any value of really numbers.}

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Answer 2

Heya !!

Here's your answer !!!

$= {4}^{x} - {4}^{x - 1} = 24 \\ = {4}^{x} - \frac{ {4}^{x} }{ {4}^{1} } = 24 \: \: \: \: \: (since \: {a}^{m - n} = \frac{ {a}^{m} }{ {a}^{n} } ) \\ = {4}^{x} (1 - ( \frac{1}{4} )) = 24 \\ = {4}^{x} (( \frac{3}{4} )) = 24 \\ = {4}^{x} = 24 \times ( \frac{4}{3} ) = 32 \\ = ( {2}^{2} )x = 5 \\ = {2}^{2} = 2 \\ comparing \: both \: side \: we \: get \\ 2x = 5 \\ hence \: x \: = \frac{5}{2} \\ now \: consider \\= ( {2x}^{2} ) = {(2( \frac{5}{2} )}^{2} \\ = {(5)}^{ \frac{5}{2} } \\ = {(55)}^{ \frac{1}{2} } \\ = { \sqrt{5} }^{5} \\ = 25 \sqrt{5}$

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