Question

If 4^x-4^x-1=24 , then the value of (2x)^x is

Answer 1

Given, 4^x-(4^(x-1))=24

=> 4^(x-1)[4-1]=24

=> 4^(x-1)=24/3=8

=> 2^(2x-2)=2^3

=> 2x-2=3

=> 2x=5

=> x=5/2

Then the value of (2x)^x

=> (2 * 5/2)^5/2

=> (5)^5/2

=> 25√5

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