Question

If 4(x+c)² + y² = 4a²
& a²-b²= c²;

Then Proof that----
x²/a² + y²/b² = 1, [ The equation of Ellipse ]​

Answer 1

Step-by-step explanation:

Answer

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Applying A.M≥G.M inequality,we have

a2+x2≥2ax

b2+y2≥2by

c2+z2≥2cz

Adding, a2+b2+c2+x2+y2+z2≥2(9x+by+cz).Using the given conditions,it reduces to

2≥2(ax+by+cz)⇒ax+by+cz≤1