Question

if 4 x square + kx + 9 equals to zero has two roots then K value is what​

Answer 1

4x² + kx + 9 = 0

$k = \frac{ - 9 - 4 {x}^{2} }{x}$

$4 {x}^{2} + ( \frac{ - 9 - 4 {x}^{2} }{ x} ) \times x + 9 = 0 \\ 4 {x }^{2} + - 9 - 4 {x}^{2} + 9 = 0$

LHS = RHS

HENCE

Answer 2

Here’s the answer check it out