If 4 x + ,xy=6.find the value of 2x+y
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Hi,
We know that,
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(a+b)^2. = a^2 +2ab + b^2.
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According to the problem given,
4x^2 +y^2 = 40 ------–---( 1 )
xy = 6................................( 2 )
Do the square of ( 2x+y ) ,
(2x + y)^2 = (2x)^2 + 2 × 2×x×y + y^2
= 4x^2 + 4xy + y^2
= 4x^2 + y^2 + 4xy
= 40 + 4 × 6
[from ( 1 ) and ( 2 ) ]
(2x+y)^2 = 40 + 24
= 64
Therefore ;
2x + y = ±√64
= ± 8. ANSWER
I hope this help you.
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