Question

If 4^x+y = 1 and 4^x-y = 1 find the values of x and y​

Answer 1

Answer:

${4}^{x + y} = 1 \: and \: {4}^{x - y} = 1$

${4}^{x + y - x - y} = 1$

${4}^{0} = 1$

$1$

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