Question

If 4, x1, x2, x3, 28 are in A.P then find x3.

Answer 1

hope it will help uhh

Answer 2

a=4, l= 28, and n=5

T5= 28

a +(n -1)d = 28

=> 4+(5-1)d = 28

=> 4d= 24 =>d=6

Hence x3 = 28-6 = 22.

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