Question

If 4, x₁, x₂, x₃, 28 are in AP then find x₃ *

Answer 1

Answer:

hope you got your answer

Answer 2

Answer:

a=4,n=5

So,

tn=a+(n-1)d

28=4+5-1×d

28=4+4d

28-4=4d

24=4d

d=6

hence,a+(n-1)d=tn

4+4-1×6=22

therefore , x3 =22

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