Question

If 4 x² (1-1) and Vaxy,
then a(u, v)
a (x,y)​

Answer 1

Answer:

Answer:

\huge x = 2x=2

Step-by-step explanation:

{(x + 2)}^{2} = 2 {x}^{2}(x+2)

2

=2x

2

By using the algebraic identity: (a+b)² = a² + 2ab + b², we get:

= > {x}^{2} + (2 \times x \times 2) + {2}^{2} = 2 {x}^{2}=>x

2

+(2×x×2)+2

2

=2x

2

= > {x}^{2} + 4x + 4 = 2 {x}^{2}=>x

2

+4x+4=2x

2

= > 2 {x}^{2} - {x}^{2} = 4x + 4=>2x

2

−x

2

=4x+4

= > {x}^{2} - 4x + 4 = 0=>x

2

−4x+4=0

= > {(x)}^{2} - (2 \times x \times 2) + {(2)}^{2} = 0=>(x)

2

−(2×x×2)+(2)

2

=0

= > {(x - 2)}^{2} = 0=>(x−2)

2

=0

= > x - 2 = 0=>x−2=0

= > x = 2=>x=2