Math, asked by adarshgoudru7, 2 months ago

If 40 kg of fish is required in a marriage reception
having 250 guests, then what will be the additional
quantity of fish required for 300 guests?​

Answers

Answered by lavanyaaa21
4

Answer:

48 kgs fish will be needed for 300 guest

Step-by-step explanation:

250 guest = 40 kg fish

1 guest =40/250 = 0.16

300 guest = 0.16x300 = 48

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Answered by anoo24
2

Step-by-step explanation:

for 250 guests - 40 kg is required = 40000g

for a guest - 40000 / 250

= 160 g

for 300 guests = 160 × 300

=48000g

= 48 kg

additional quantity of fish = fish for 300 guests - fish for 250 guests

= 48-40

= 8 kg additional fish

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