Question

If 40% of 80 is "y" more than 20% of 90, find "y".​

Answer 1

$\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}$

$\huge\tt\red{\bold{\underline{\underline{❥Question᎓}}}}$If 40% of 80 is "y" more than 20% of 90, find "y".

$\huge\tt{\boxed{\overbrace{\underbrace{\blue{Answer</p><p> }}}}}$

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40% of 80=y+20%of 90

$\frac{40}{100} \times 80 = y + \frac{20}{100} \times 90$

Here ,100 & 80 is cancelled by 20 and on Right side 20/100 is cancelled by 20 and then 90 by 5.

$⟹\frac{2}{5} \times 80 = y + \frac{1}{5} \times 90$

$⟹2 \times 16 = y + 18$

$⟹32 = y + 18$

$⟹y = 32 - 18$

$\huge\tt{\boxed{\red{y = 14}}}$

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