Question

If 40% of sum of two numbers is equal to 60% of their difference, then find the relation between two numbers.​

Answer 1

Answer:

refer to the attachment....

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Answer 2

$\fbox{\fbox{\orange{\large{\mathfrak{Answer:-}}}}}$

Second number is 5 times of first number.

$\fbox{\fbox{\red{\large{\mathfrak{Solution:-}}}}}$

Let the two numbers be x and y

$so \: 0.4(x + y) = 0.6(x - y)$

$\frac{(x + y)}{(x + y)} = \frac{0.6 + 0.4}{0.6 + 0.4}$

$\frac{x}{y} = \frac{10}{2}$

$x = 5y$