Question

if 40%of X is 120, find 60%ofX​

Answer 1

Given:

$\\ \\ 40\% \: \: of \: \: x \: \: = 120 \\ \\ \\ \frac{40}{100} \times \: x \: = 120 \\ \\ \\ x = \frac{120 \times 100}{40} \\ \\ \\ x= 300 \: \: \: \: \: answer \: \\ \\ \\ \\ \\ but \: \: now \: \: we \: \: have \: \: t o\: \: find \\ \: \: 60\% \: \: of \: \: x \: \: \\ \\\ \\ \\ \frac{60}{100} \times x = 120\\ \\ \\ x = \frac{120 \times 100}{60} \\ \\ \\ x = 200 \: \: \: answer$

Answer 2

Answer:

The converse of this theorem is also true; that is, if two lines kk and ll are cut by a transversal so that the alternate interior angles are congruent, then k∥lk∥l .The converse of this theorem is also true; that is, if two lines kk and ll are cut by a transversal so that the alternate interior angles are congruent, then k∥lk∥l .The converse of this theorem is also true; that is, if two lines kk and ll are cut by a transversal so that the alternate interior angles are congruent, then k∥lk∥l .The converse of this theorem is also true; that is, if two lines kk and ll are cut by a transversal so that the alternate interior angles are congruent, then k∥lk∥l .