if 40 sweets are to be distribute between sita and geeta in the ratio 7:3, how much would each get
Answers
Answered by
2
Answer:
28, 12
Explanation:
7x + 3x = 40
10x = 40
x = 40/10
x = 4
7x = 28
3x = 12
Answered by
18
☘️ Given :-
Sweets are to be distribute between sita and geeta in the ratio 7:3
☘️ To Find :-
how much would each get ?
☘️ Solution :-
40 Sweets are to be distribute between sita and geeta in the ratio 7:3
Let,
- Sita = 7x
- Geetha = 3x
- Total = 40 Sweets
Now,
=> Sita gets + Geetha gets = 40 Sweets
=> 7x + 3x = 40
=> 10x = 40
=> x = 40/10
=> x = 4
Sita = 7x = 4×7 = 28
Geetha = 3x = 4×3 = 12
Hence,
Sita gets 28 sweets
Geetha gets 12 sweets
☘️ Verification :-
=> 28 + 12 = 40 Sweets
=> 40 = 40
Hence, proved !
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