Question

If 400 g boiling water at 100 0C is poured on a large slab of ice at 0 0C, how much ice will melt? (Specific heat capacity of water is 1 cal/g 0C and Latent heat of fusion of ice is 80 cal/g).

Answer 1

Answer:

⇒500 gms of ice melts

Given,

If 400g boiling water at 100°C is poured on a large slab of ice at 0°C. specific heat capacity of water, S = 1 cal/g/°C and latent heat of fusion of ice, Lf = 80 cal/g

To find,

The amount of ice will melt.

amount of water, m₁ ⇒400g

change in temperature, ∆T ⇒ 100° C

from calorimetry,heat lost by water = heat gained by ice

⇒m₁S∆T = mLf

⇒400g × 1cal/g/°C × 100°C = mLf

⇒40000 = m × 80 cal/g

⇒m = 500 g

Therefore 500g of ice will melt.

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