If 400 g boiling water at 100 0C is poured on a large slab of ice at 0 0C, how much ice will melt? (Specific heat capacity of water is 1 cal/g 0C and Latent heat of fusion of ice is 80 cal/g).
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Answer:
⇒500 gms of ice melts
Given,
If 400g boiling water at 100°C is poured on a large slab of ice at 0°C. specific heat capacity of water, S = 1 cal/g/°C and latent heat of fusion of ice, Lf = 80 cal/g
To find,
The amount of ice will melt.
amount of water, m₁ ⇒400g
change in temperature, ∆T ⇒ 100° C
from calorimetry,heat lost by water = heat gained by ice
⇒m₁S∆T = mLf
⇒400g × 1cal/g/°C × 100°C = mLf
⇒40000 = m × 80 cal/g
⇒m = 500 g
Therefore 500g of ice will melt.
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