Question

If 400 joule work has done to moves an object 40 meter of mass 5 kg then what would be the acceleration of the object

Answer 1

2 m/s² is the required answer.

GIVEN:

• Work done, w = 400 J
• Displacement, d = 40 m
• Mass , m = 5 kg

TO FIND:

Acceleration of the object , a

FORMULAE:

• According to Newton's second law of motion, f = ma

• Work done, w = f × d

SOLUTION:

STEP 1: TO FIND FORCE:

$w = f \times d \\ \\ 400 = f \times 40 \\ \\ f = \frac{400}{40} \\ \\ f = 10 \: newton$

Force is 10 N

STEP 2: TO FIND ACCELERATION:

$f = ma \\ \\ 10 = 5a \\ \\ a = \frac{10}{5} \\ \\ a = 2 \: \frac{m}{ {s}^{2} }$

ANSWER:

Acceleration of the object is 2 m/s²

IMPORTANT POINTS:

• Newton's second law of motion states that "Force is defined as the rate of change of momentum."

• f = ma is the result of Newton's second law of motion , when mass remains constant.

• Work done is defined as the product of force and displacement.

• Force is equal to the product of mass and acceleration.

• Force and Acceleration are vector quantities , having both magnitude and direction.

• Work done and mass are scalar quantities , having magnitude alone. They do not have specified direction.