Question

If 4000 J of heat is used to heat the iron rod of mass 20 kg from 40°C to 60°C, determine the

Specific heat capacity of that iron rod.​

Answer 1

Answer:

Please mark BRAINLIEST...

Answer 2

Answer:

The specific heat capacity of the given iron rod, c, calculated is $0.01J/g-\textdegree C$.

Explanation:

Given data,

The heat used by the system to heat the iron rod, Q = $4000J$

The mass of the iron rod, m = $20kg$ = $20\times 10^{3}g$

The initial temperature of the iron rod, T₁ = $40\textdegree C$

The final temperature of the iron rod, T₂ = $60\textdegree C$

The change in temperature of the iron rod, ΔT = $T_{2} -T_{1}$ = $(60 - 40)\textdegree C$ = $20\textdegree C$.

The specific heat capacity of the given iron rod, c =?

By using the formula of heat transfer ( Q ), we can find out the specific heat capacity of the iron rod:

• $Q = mc \Delta T$
• c = $\frac{Q}{m\Delta T}$
• c = $\frac{4000}{20\times 10^{3} \times 20}$
• c = $\frac{4}{400}$
• c = $0.01J/g-\textdegree C$

Hence, the specific heat capacity of the given iron rod, c = $0.01J/g-\textdegree C$.